A) Acceleration \[=-{{k}_{0}}x+{{k}_{1}}{{x}^{2}}\]
B) Acceleration \[=-\,k\,(x+a)\]
C) Acceleration \[=\,k\,(x+a)\]
D) Acceleration \[=kx\] where \[k,\,{{k}_{0}},\,{{k}_{1}}\] and a are all positive.
Correct Answer: B
Solution :
| Key Idea Acceleration \[\propto -\](displacement). |
| \[A\,\propto -y\] |
| \[A=-{{\omega }^{2}}y\] |
| \[A=-\frac{k}{m}y\] |
| \[A=-ky\] |
| Here, \[y=x+a\] |
| \[\therefore \] acceleration \[=-k(x+a)\] |
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