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NEET Physics Simple Harmonic Motion NEET PYQ-Simple Harmonic Motion

  • question_answer
    Two waves are represented by the equations \[{{y}_{1}}-a\sin (\omega t+kx+0.57)m\] and \[{{y}_{2}}-a\cos \,(\omega t+kx)m,\] in, where x is in metre and t in second. The phase difference between them is                                                                                                                                 [AIPMT (S) 2011]

    A)  1.25 rad        

    B)       1.57 rad          

    C)  0.57 rad        

    D)       1.0 rad

    Correct Answer: D

    Solution :

    \[{{y}_{1}}=a\sin (\omega t+kx+0.57)m\]
    and       \[{{y}_{2}}=a\cos (\omega t+kx)m\]
    or         \[{{y}_{2}}=a\sin \left( \frac{\pi }{2}+\omega t+kx \right)m\]
    Phase difference
    \[\Delta \phi ={{\phi }_{2}}-{{\phi }_{1}}\]
    \[=\frac{\pi }{2}-0.57\]
    \[=1.57-0.57\]
    \[=1\,\,\text{rad}\]


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