NEET Physics Simple Harmonic Motion NEET PYQ-Simple Harmonic Motion

  • question_answer
    A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force \[F\sin \omega t\]. If the amplitude of the particle is maximum for \[\omega ={{\omega }_{1}}\] and the energy of the particle maximum for\[\omega ={{\omega }_{2}},\] then :                                                          [AIPMT 1998]

    A)  \[\omega ={{\omega }_{0}}\] and \[{{\omega }_{2}}\ne {{\omega }_{0}}\]

    B)                   \[{{\omega }_{1}}={{\omega }_{0}}\] and \[{{\omega }_{2}}={{\omega }_{0}}\]

    C)       \[{{\omega }_{1}}\ne {{\omega }_{0}}\] and\[{{\omega }_{2}}={{\omega }_{0}}\]       

    D)       \[{{\omega }_{1}}\ne {{\omega }_{0}}\] and  \[{{\omega }_{2}}\ne {{\omega }_{0}}\] where \[{{\omega }_{0}}\to \] natural angular frequency of oscillations of particle.

    Correct Answer: C

    Solution :

    In driven harmonic oscillator, the energy is maximum at \[{{\omega }_{2}}={{\omega }_{0}}\] and amplitude is maximum at frequency \[{{\omega }_{1}}<{{\omega }_{0}}\] in the presence of damping. So \[{{\omega }_{1}}\ne {{\omega }_{0}}\] and \[{{\omega }_{2}}={{\omega }_{0}}\].


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