A) \[{{U}_{1}}=0\]
B) \[{{U}_{3}}=0\]
C) \[{{U}_{1}}>\text{ }{{U}_{2}}\]
D) \[{{U}_{2}}>\text{ }{{U}_{1}}\]
Correct Answer: D
Solution :
[d] Maximum amount of emitted radiation corresponding to \[{{\lambda }_{m}}=\frac{b}{T}\] |
\[{{\lambda }_{m}}=\frac{2.88\times {{10}^{6}}\,nmK}{5760K}=500\,nm\] |
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