NEET Physics Simple Harmonic Motion NEET PYQ-Simple Harmonic Motion

  • question_answer
    The radius of circle, the period of revolution, initial position and sense of revolution are indicated in the fig.
                                                                                      [NEET 2019]   
    Y-projection of the radius vector of rotating particle P is:

    A) \[(y)t=3cos\left( \frac{3\pi t}{2} \right)\], where y in m

    B)  \[(y)t=3cos\left( \frac{\pi t}{2} \right)\], where y in m

    C)  \[(y)t=-3cos2\pi t\], where y in m

    D)  \[(y)t=4\sin \left( \frac{\pi t}{2} \right)\], where y in m

    Correct Answer: B

    Solution :

    [b]
               
    \[y=r\text{ }cos\theta \]
    \[y=3\text{ }cos\omega t\]
    \[y=3\text{ }cos\frac{2\pi }{4}.t\]
    \[y=3\text{ }cos\frac{2\pi }{2}\]


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