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  • question_answer
    The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 moles of P and 2 moles of Q would be: [AIPMT (S) 2005]

    A) 140 torr

    B) 20 torr

    C) 68 torr

    D) 72 torr

    Correct Answer: D

    Solution :

    [d] Mole fraction of \[P=\frac{3}{3+2}=\frac{3}{5}\]
                Mole fraction of \[Q=\frac{2}{3+2}=\frac{2}{5}\]
                Hence, total vapour pressure
                = Mole fraction of P × V. P of P + mole fraction of Q × V.P. of Q
                \[=\left( \frac{3}{5}\times 80+\frac{2}{5}\times 60 \right)=48+24\]
                \[=72\,Torr\]


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