A) \[-1.12\text{ }K\]
B) \[0.56\text{ }K\]
C) \[1.12\text{ }K\]
D) \[-0.56\,K\]
Correct Answer: C
Solution :
| [c] \[\underset{\begin{smallmatrix} weak\,acid \\ 1 \\ 1-\alpha \end{smallmatrix}}{\mathop{HX}}\,\rightleftharpoons \,\underset{\begin{smallmatrix} 0 \\ \alpha \end{smallmatrix}}{\mathop{{{H}^{+}}}}\,+{{\underset{\begin{smallmatrix} 0 \\ \alpha \,\, \end{smallmatrix}}{\mathop{{{X}^{-}}}}\,}_{(at\ equilibrium)}}\] |
| \[\alpha =20%\,dissociation\] |
| i.e., \[\alpha \] = 0.2 |
| \[i=1-\alpha +\alpha +\alpha \] |
| \[=1+\alpha =1+0.2=1.2\] |
| \[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\] |
| \[=1.2\times 1.86\,K\,kg\,mo{{l}^{-1}}\,\times 0.5\] |
| = 1.12 K |
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