A) 173.9 mmHg
B) 615.0 mmHg
C) 347.9 mmHg
D) None of these
Correct Answer: D
Solution :
[d] Number of moles of \[CHC{{l}_{3}},\] |
\[{{n}_{A}}=\frac{w}{M}\] |
\[=\frac{25.5}{119.5}\] |
\[=0.213\] |
Number of moles of \[C{{H}_{2}}C{{l}_{2}},\] |
\[{{n}_{B}}=\frac{40}{85}=0.47\] |
Mole fraction of \[CHC{{l}_{3}}\] |
\[{{\chi }_{A}}=\frac{{{n}_{A}}}{{{n}_{A}}+{{n}_{B}}}\] |
\[=\frac{0.213}{0.683}=0.31\] |
Mole fraction of \[C{{H}_{2}}C{{l}_{2}},\] |
\[{{\chi }_{B}}=1-{{\chi }_{A}}\] |
\[=1-0.31=0.69\] |
\[\because \] \[{{p}_{total}}={{p}_{A}}{{\chi }_{A}}+{{p}_{B}}{{\chi }_{B}}\] |
\[=200\times 0.31+41.5\times 0.69\] |
\[=62+28.63\] |
\[=90.63mm\,Hg\] |
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