NEET Chemistry NEET PYQ-Solutions

  • question_answer
    The freezing point depression constant for water is \[-{{1.86}^{o}}C\,{{m}^{-1}}\]. If 5.00 g \[N{{a}_{2}}S{{O}_{4}}\] is dissolved in \[45.0g\,{{H}_{2}}O,\] the freezing point is changed by \[-3.82{}^\circ C\]. Calculate the van't Hoff factor for\[N{{a}_{2}}S{{O}_{4}}\].               [AIPMT (S) 2011]

    A) 2.63

    B) 3.11     

    C) 0.381

    D) 2.05

    Correct Answer: A

    Solution :

    [a] \[\Delta {{T}_{f}}=i\times {{K}_{f}}\cdot m\]
    or         \[i=\frac{\Delta {{T}_{f}}\times {{W}_{solvent}}}{{{K}_{f}}\times {{n}_{solute}}\times 1000}\]
                \[=\frac{3.82\times 45}{1.86\times \left( \frac{5}{142} \right)\times 1000}\]
                            \[=2.63\]


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