A) X is undergoing dissociation in water.
B) Molecular mass of X is greater than the molecular mass of V.
C) Molecular mass of X is less than the molecular mass of V.
D) V is undergoing dissociation in water while X undergoes no change.
Correct Answer: A
Solution :
| [a] Molality of solution X = molality of solution Y |
| = 0.2mol/kg |
| We know that, elevation in the boiling point \[(\Delta {{T}_{b}})\] of a solution is proportional to the molal concentration of the solution i.e. |
| \[\Delta {{T}_{b}}\propto m\,\,\,or\,\Delta {{T}_{b}}={{K}_{b}}m\] |
| where, m is the molality of the solution and \[{{K}_{b}}\] is molal boiling point constant or ebullioscopic constant. |
| \[\therefore \] By elevation in boiling point relation |
| \[\Delta {{\Tau }_{b}}=i{{K}_{b}}m\,\,\text{or}\,\Delta {{\text{T}}_{b}}\propto i\] |
| where, \[i\] is van't Hoff is factor |
| Since, \[\Delta {{T}_{b}}\], of solution X is greater than \[\Delta {{T}_{b}}\] of solution Y. |
| (Observed colligative property is greater than normal colligative property). |
| \[\therefore \] \[i\] of solution X > i of solution Y |
| \[\therefore \] Solution X undergoing dissociation. |
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