A) 1 g of Mg(s) [Atomic mass of Mg = 24]
B) 1 g of O2(g) [Atomic mass of O = 16]
C) 1 g of Li(s) [Atomic mass of Li = 7]
D) 1 g of Ag(s) [Atomic mass of Ag = 108]
Correct Answer: C
Solution :
| [c] |
| Number of Mg atoms \[=\frac{1}{24}\times {{N}_{A}}\] |
| Number of O atoms \[=\frac{1}{32}\times 2\times {{N}_{A}}\] |
| Number of Li atoms \[=\frac{1}{7}\times {{N}_{A}}\] |
| Number of Ag atoms \[=\frac{1}{108}\times {{N}_{A}}\] |
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