A) \[{{\overline{KE}}_{\,CO}}\,<\,{{\overline{KE}}_{{{N}_{2}}}}\]
B) \[{{\overline{KE}}_{\,CO}}\,>\,{{\overline{KE}}_{{{N}_{2}}}}\]
C) \[{{\overline{KE}}_{\,CO}}\,=\,{{\overline{KE}}_{{{N}_{2}}}}\]
D) Cannot be predicted unless volumes of die gases are given
Correct Answer: C
Solution :
\[KB=\frac{3}{2}\,RT\] (for one mole of a gas) |
The temperature is constant and kinetic energy is independent on molecular weights. So, |
\[{{\overline{KE}}_{CO}}={{\overline{KE}}_{{{N}_{2}}}}\] |
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