A) \[-\,41\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[-\,1312\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[-\,164\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[-\,82\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
| The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\] is \[-328\text{ }kJ\text{ }mo{{l}^{-1}}\] because |
| \[{{E}_{2}}=-\frac{1312}{{{2}^{2}}}\,kJ\,mo{{l}^{-1}}\] |
| \[\therefore \] \[{{E}_{n}}=\frac{1312}{{{n}^{2}}}kJ\,mo{{l}^{-1}}\] |
| If \[n=4\] |
| \[\therefore \] \[{{E}_{4}}=-\frac{1312}{{{n}^{2}}}kJ\,mo{{l}^{-1}}\,=-82\,kJ\,mo{{l}^{-1}}\] |
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