A) \[{{\lambda }_{1}}=2{{\lambda }_{2}}\]
B) \[{{\lambda }_{1}}=4{{\lambda }_{2}}\]
C) \[{{\lambda }_{1}}=\frac{1}{2}{{\lambda }_{2}}\]
D) \[{{\lambda }_{1}}={{\lambda }_{2}}\]
Correct Answer: A
Solution :
| \[{{E}_{1}}=25\,eV,{{E}_{2}}=50\,eV\] |
| \[{{E}_{1}}=\frac{hc}{{{\lambda }_{1}}}\] |
| and \[{{E}_{2}}=\frac{hc}{{{\lambda }_{2}}}\] |
| or \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\] or \[\frac{25}{50}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\] |
| or \[{{\lambda }_{1}}=2{{\lambda }_{2}}\] |
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