A) \[6.67\times {{10}^{15}}\]
B) \[6.67\times {{10}^{11}}\]
C) \[4.42\times {{10}^{-15}}\]
D)
\[4.42\times {{10}^{-18}}\] Correct Answer:
D Solution :
Given, \[\lambda =45nm=45\times {{10}^{-9}}m\] \[[\because \,1nm={{10}^{-9}}m]\] Hence, \[E=\frac{6.63\times {{10}^{-34}}js\times 3\times {{10}^{8}}m{{s}^{-1}}}{45\times {{10}^{-9}}m}\] \[=4.42\times {{10}^{-18}}\text{J}\] Hence, the energy corresponds to light of wavelength 45 nm is \[4.42\times {{10}^{-18}}J.\]
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