A) 104, 71 and 71
B) 71, 71 and 104
C) 175, 104 and 71
D) 71, 104 and 71
Correct Answer: D
Solution :
[d] \[_{\,\,71}^{175}Lu\] |
No. of Protons = 71 = No. of Electrons |
No. of Neutrons = Mass no. No. of Protons |
\[=17571\] |
\[=104\] |
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