A) one fifth
B) five
C) one
D) two
Correct Answer: D
Solution :
[d] In alkaline solution, \[KMn{{O}_{4}}\,\]is reduced to \[Mn{{O}_{2}}\,\](colorless). |
\[\frac{\begin{align} & 2KMn{{O}_{4}}+2{{H}_{2}}O\xrightarrow[{}]{{}}2Mn{{O}_{2}}+2KOH+3\,[O] \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,KI\,+3\,[O]\,\xrightarrow[{}]{{}}KI{{O}_{3}} \\ \end{align}}{2KMn{{O}_{4}}+2{{H}_{2}}O+KI\xrightarrow[{}]{{}}2Mn{{O}_{2}}+2KOH+KI{{O}_{3}}}\] |
Hence, two moles of KMnO4 are reduced by one mole of KI. |
You need to login to perform this action.
You will be redirected in
3 sec