A) Vanadium (Z = 23)
B) Chromium (Z = 24)
C) Iron (2 = 26)
D) Manganese (Z = 25)
Correct Answer: D
Solution :
[d] In 23V = 1s2, 2s2 2p6, 3s2 3p6 3d3, 4s2 |
Third electron which is removed in third ionisation potential enthalpy belongs to 3d3 sub-shell. |
24Cr = 1s2, 2s2 2p6, 3s2 3p6 3d6 4s2 |
Third electron which is removed m third ionisation potential enthalpy belongs to 3d5 sub-shell. |
26Fe = 1s2, 2s2 2p6, 3s2 3p6 3d6, 4s2 |
Third electron which is removed in third ionisation potential enthalpy belongs to 3d6 sub-shell. |
2SMn = 1s2, 2s2 2p6, 3s2 3p6 3d5 4s2 |
Third electron which is removed in third ionisation potential belongs to 3d5 sub-shell. |
In all elements shell and sub-shells are same. Required amount of energy (enthalpy) is based upon the stability of d-subshell. |
The 3d5 sub-shell has highest stability in all because it is half filled sub-shell (while other are incomplete). So Mn shows highest third ionisation potential or enthalpy. |
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