A) 3d3, 4s2
B) 3d5, 4s1
C) 3d5, 4s2
D) 3d2, 4s2
Correct Answer: C
Solution :
[c] Key Idea Number of oxidation states exhibited by d-block elements is the sum of number of electrons (unpaired) in d-orbitals and number of electrons in s-orbital. |
\[15\,\Omega \] |
\[240\,\Omega \] |
\[15\,\Omega \] |
\[{{T}_{1}}\] |
Hence, element with \[{{T}_{2}}({{T}_{1}}>{{T}_{2}}).\] configuration exhibits largest number of oxidation states. |
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