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NEET Chemistry NEET PYQ-The d-and f-Block Elements

  • question_answer
    Number of moles of \[MnO_{4}^{-}\] required to oxidize one mole of ferrous oxalate completely in acidic medium will be                       [AIPMT (S) 2008]

    A) 0. 6 mole

    B) 0.4 mole

    C) 7.5 moles

    D) 0.2 mole

    Correct Answer: A

    Solution :

    [a] Key idea: \[3MnO_{4}^{-}+5{{C}_{2}}O_{4}^{2-}+24{{H}^{+}}\xrightarrow[{}]{{}}\] 
    \[3M{{n}^{2+}}+10C{{O}_{2}}+12{{H}_{2}}O\]
    \[\therefore \]Number of moles of \[MnO_{4}^{-}\]required to oxidise 5 moles of\[{{C}_{2}}O_{4}^{2-}=3\]
    \[\therefore \]Number of moles of \[MnO_{4}^{-}\]required- to oxidise 1 mole of \[{{C}_{2}}O_{4}^{2-}=\frac{3}{5}\]\[=0.6mol\]


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