A) \[T{{i}^{4+}}\]
B) \[C{{u}^{+}}\]
C) \[Z{{n}^{2+}}\]
D) \[C{{r}^{3+}}\]
Correct Answer: D
Solution :
| [d] \[C{{r}^{3+}}=1{{s}^{2}},\text{ }2{{s}^{2}}2{{p}^{6}},\text{ }3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\] (coloured) |
| \[Z{{n}^{2+}}=1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\] (colourless) |
| \[C{{u}^{+}}=1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}},\text{ }3{{p}^{6}}3{{d}^{10}}\] (colourless) |
| \[T{{i}^{4+}}=\text{ }1{{s}^{2}}2{{s}^{2}}2{{p}^{6}},\text{ }3{{s}^{2}}3{{p}^{6}}\] (colourless) |
| (Colour is produced due to presence of unpaired electron.) |
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