NEET Chemistry NEET PYQ-The Solid State

  • question_answer
    If ‘a’ stands for the edge length of the cubic systems: simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these systems will be respectively, [AIPMT (S) 2008]

    A) \[\frac{1}{2}a;\frac{\sqrt{3}}{4}a:\frac{1}{2\sqrt{2}}a\]

    B) \[\frac{1}{2}a;\sqrt{3}a:\frac{1}{\sqrt{2}}a\]

    C) \[\frac{1}{2}a:\frac{\sqrt{3}}{2}a:\frac{\sqrt{2}}{2}a\]

    D) \[1a:\sqrt{3}a:\sqrt{2}a\]

    Correct Answer: A

    Solution :

    [a] For simple cubic,
    a = 2r
    \[\therefore \]\[r=\frac{a}{2}\]For body centred cubic, \[a=\frac{4r}{\sqrt{3}}\]
    \[r=\frac{\sqrt{3}a}{4}\]
    For face centred cubic,
    \[a=2\sqrt{2}r\]
    \[r=\frac{a}{2\sqrt{2}}\]
    Hence, the ratio of radii in simple cubic, body centred cubic and face centred cubic is
    \[\frac{a}{2}:\frac{\sqrt{3}a}{4}:\frac{a}{2\sqrt{2}}\]


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