A) \[{{A}_{2}}{{B}_{2}}\]
B) \[A{{B}_{3}}\]
C) AB
D) \[{{A}_{3}}B\]
Correct Answer: B
Solution :
[b] A atoms are at corners of a cube |
So, the number of A atoms per unit cell \[=8\times \frac{1}{8}=1\]. |
Similarly, B atoms are present at face centres of a cube. |
So, the number of S atoms per unit cell \[=6\times \frac{1}{2}\]. |
Hence, the compound is \[A{{B}_{3}}\] |
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