Consider the following reaction [AIPMT (S) 2009] |
\[\text{Phenol}\,\xrightarrow[{}]{\text{Zndust}}X\xrightarrow[\text{Anhydrous }AlC{{l}_{3}}]{C{{H}_{3}}Cl}Y\xrightarrow[{}]{\text{Alkaline }KMn{{O}_{4}}}Z,\] the product Z is |
A) toluene
B) benzaldehyde
C) benzoic acid
D) benzene
Correct Answer: C
Solution :
[c] Key Idea (i) Zn dust converts OH group intoH. |
(ii) Reaction with \[RX+{{H}_{2}}\xrightarrow[{}]{{}}RH+HX\] in presence of anhy. |
\[RX+Mg\xrightarrow[{}]{{}}RMgX\] is called FriedelCraft's alkylation. |
(iii) Alkaline \[\text{mo}{{\text{l}}^{\text{-1}}}\] converts complete carbon chain which is directly attached with benzene ring, into -COOH group. |
You need to login to perform this action.
You will be redirected in
3 sec