A) 335 pm
B) 250 pm
C) 200 pm
D) 300 pm
Correct Answer: A
Solution :
[a] For body centred cubic (bcc) lattice, distance between two oppositely charged ions, |
\[d=\frac{\sqrt{3}a}{2}=\frac{\sqrt{3}\times 387}{2}pm\] |
\[=335.15\,pm\] |
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