A) 154 pm
B) 352 pm
C) 527 pm
D) 264 pm
Correct Answer: B
Solution :
| [b] \[\rho =\frac{Z\times M}{{{N}_{A}}\times {{a}^{3}}}\] |
| For bcc structure |
| \[Z=2,\,\,\rho =530\,kg\,{{m}^{-3}}=0.530\,g\,c{{m}^{-3}}\] |
| \[0.530=\frac{2\times 6.94}{6.02\times {{10}^{23}}\times {{a}^{3}}}\] |
| \[{{a}^{3}}=4.348\times {{10}^{-23}}\,c{{m}^{3}}\] |
| \[a=3.52\times {{10}^{-8}}\,cm\] |
| \[a=352\,pm\] |
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