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NEET Chemistry NEET PYQ-The Solid State

  • question_answer
    The second order Bragg diffraction of X-rays with \[\lambda =1.0\,\overset{\text{o}}{\mathop{\text{A}}}\,\]  from a set of parallel planes in a metal occurs at an angle \[60{}^\circ \]. The distance between the scattering planes in the crystals is: [AIPMT 1998]

    A) \[0.575\,\overset{o}{\mathop{A}}\,\]

    B) \[1.00\,\overset{o}{\mathop{A}}\,\]

    C) \[2.00\,\overset{o}{\mathop{A}}\,\]

    D) \[1.17\,\overset{o}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

    [d] According to Bragg’s equation 
                            \[n=2\,\lambda =1\,\theta ={{60}^{o}}\,d=?\]
                            \[2\times 1=2\times d\times \sin {{60}^{o}}\]
                            \[2\times 1=2\times d\times \frac{\sqrt{3}}{2}\]
                            \[d=\frac{2}{\sqrt{3}}=\frac{2}{1.7}=1.17\,{\AA}\]


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