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NEET Chemistry NEET PYQ-The Solid State

  • question_answer
    An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is                                       [NEET 2020]

    A) \[\frac{\sqrt{2}}{4}\times 288\,\,pm\]

    B) \[\frac{4}{\sqrt{3}}\times 288\,\,pm\]

    C) \[\frac{4}{\sqrt{2}}\times 288\,\,pm\]

    D) \[\frac{\sqrt{3}}{4}\times 288\,\,pm\]

    Correct Answer: D

    Solution :

    [d] For BCC,
                \[\sqrt{3}a=4r\]              a = edge length
                \[r=\frac{\sqrt{3}a}{4}\times 288\]
                Given, \[a=288\,\,pm\]
                \[r=\frac{\sqrt{3}}{4}\times 288\]


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