A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is [AIPMT (S) 2012] |
A) \[2\,pV\]
B) \[4\,pV\]
C) \[\frac{1}{2}pV\]
D) \[pV\]
Correct Answer: A
Solution :
For given cyclic process, \[\Delta U=0\] |
\[\therefore \] \[Q=W\] |
Also, \[W=-\] area enclosed by the curve |
\[=AB\times AD\] |
\[=(2p-p)(3V-V)\] |
\[=-p\times 2V\] |
\[\therefore \] Heat rejected \[=\,2\,pV\] |
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