A) 2.365 W
B) 23.65 W
C) 236.5 W
D) 2365 W
Correct Answer: C
Solution :
[c] \[\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\] |
(Where \[{{Q}_{2}}\] is heat removed) |
\[\Rightarrow \] \[\frac{600\times 4.2}{W}=\frac{277}{303-277}\] |
\[\Rightarrow \] \[W=236.5\,\text{joule}\] |
\[\Rightarrow \] \[\text{Power}\,\,=\,\,\frac{W}{t}=\frac{236.5\,\text{joule}}{1\,\sec }=236.5\,\,watt.\] |
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