question_answer

An ideal gas is compressed to half its initial volume by means of several process. Which of the process results in the maximum work done on the gas?                                                                                                         [NEET (Re) 2015]

A)  Adiabatic         

B)       Isobaric

C)  Isochoric          

D)       Isothermal

Correct Answer: A

Solution :

Given, ideal gas is compressed to half its initial volume i.e.

\[{{V}_{0}}=\frac{V}{2}\]

The isochoric process is one in which volume is kept constant, meaning that work done by the system will be zero i.e., \[{{W}_{\text{isochoric}}}=0\]

As we know, work dine on the gas = Area under curve i.e.

\[{{W}_{\text{ediabatic}}}>{{W}_{\text{isothermal}}}>{{W}_{\text{isochoric}}}\]