NEET Physics Thermodynamical Processes NEET PYQ-Thermodynamical Processes

  • question_answer
    The coefficient of performance of a refrigerator is 5. If the temperature inside freezer is \[-20{}^\circ C,\] the temperature of the surroundings to which it rejects heat is                                   [NEET (Re) 2015]

    A)  \[31{}^\circ C\]           

    B)       \[41{}^\circ C\]

    C)  \[11{}^\circ C\]           

    D)                   \[21{}^\circ C\]

    Correct Answer: A

    Solution :

    Key Concept Coefficient of performance \[(\beta )\] of a refrigerator is defined, as the ratio of quantity of heat removed per cycle \[({{O}_{2}})\] to the work done on the working substance per cycle to remove this heat.
    Given, coefficient of performance of a refrigerator, \[\beta =5\]
    Temperature of surface i.e. inside freezer,
    \[{{T}_{2}}=20{{\,}^{o}}C=-20+273=253\,K\]
    Temperature of surrounding i.e. heat rejected outside \[{{T}_{1}}=?\]
    So,       \[\beta =\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\Rightarrow 5=\frac{253}{{{T}_{1}}-253}\]
    \[\Rightarrow \]   \[5{{T}_{1}}-1266=253\]
    \[\Rightarrow \]   \[5{{T}_{1}}-1518\]
    \[{{T}_{1}}=\frac{1518}{5}=303.6K\]
    \[{{T}_{1}}=303.6-273=31{{\,}^{o}}C\]


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