A) \[\frac{4}{3}\]
B) 2
C) \[\frac{5}{3}\]
D) \[\frac{3}{2}\]
Correct Answer: D
Solution :
According to question |
\[p\propto {{T}^{3}}\] |
\[pV=nRT\] |
And \[p\propto {{T}^{3}}\] |
\[\Rightarrow \] \[{{p}^{2}}{{V}^{3}}=\] constant |
\[p{{V}^{3/2}}=\] constant |
\[\because \] \[p{{V}^{\gamma }}=\] constant |
\[\therefore \] \[\gamma =\frac{3}{2}\] |
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