A) \[T\Delta S<\Delta H\] and both \[\Delta H\] and \[\Delta S\] are +ve
B) \[T\Delta S>\Delta H\] and both \[\Delta H\] and \[\Delta S\] are +ve
C) \[T\Delta S=\Delta H\] and both \[\Delta H\] and \[\Delta S\] are +ve
D) \[T\Delta S>\Delta H\] and \[\Delta H\] is + ve and \[\Delta S\] is -ve
Correct Answer: B
Solution :
The spontaneity of reaction is based upon the negative value of is based upon and according to following equation (Gibbs-Helmholtz equation) |
If the magnitude of is negative, then the reaction is spontaneous, when and and are +ve, then is negative. |
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