The value of equilibrium constant of the reaction \[HI(g)\frac{1}{2}{{H}_{2}}(g)+\frac{1}{2}{{I}_{2}}\] is 8.0. |
The equilibrium constant of the reaction [AIPMT (S) 2008] |
\[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] will be |
A) \[\frac{1}{16}\]
B) \[\frac{1}{64}\]
C) 16
D) \[\frac{1}{8}\]
Correct Answer: B
Solution :
(ii) |
From Eqs (i) and (ii) |
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