question_answer

The value of equilibrium constant of the reaction \[HI(g)\frac{1}{2}{{H}_{2}}(g)+\frac{1}{2}{{I}_{2}}\] is 8.0.

The equilibrium constant of the reaction                                                                          [AIPMT (S) 2008]

\[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] will be

A)  \[\frac{1}{16}\]            

B)  \[\frac{1}{64}\]

C)  16                   

D)       \[\frac{1}{8}\]

Correct Answer: B

Solution :

(ii)

From Eqs (i) and (ii)