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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी NEET PYQ-Thermodynamics

  • question_answer
    If \[\Delta E\] is the heat of reaction for \[{{C}_{2}}{{H}_{5}}OH(l)+3{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] at constant volume, the \[\Delta H\] (heat of reaction at constant pressure) at constant temperature is:             [AIPMT 2000]

    A)  \[\Delta H=\Delta E+RT\]          

    B)  \[\Delta H=\Delta E-RT\]

    C)  \[\Delta H=\Delta E-2RT\]

    D)       \[\Delta H=\Delta E+2RT\]

    Correct Answer: B

    Solution :

    We know that
                            \[\Delta H=\Delta E+\Delta nRT\]
                where \[\Delta n=\] number of moles of gaseous product
                - number of moles  of gaseous reactant
                            \[=2-3=-1\]
                So,       \[\Delta H=\Delta E-RT\]


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