A) \[{{\Delta }_{r}}H>0\] and \[{{\Delta }_{r}}S<0\]
B) \[{{\Delta }_{r}}H<0\] and \[{{\Delta }_{r}}S>0\]
C) \[{{\Delta }_{r}}H<0\] and \[{{\Delta }_{r}}S<0\]
D) \[{{\Delta }_{r}}H>0\] and \[{{\Delta }_{r}}S>0\]
Correct Answer: C
Solution :
| [c] Given reaction, \[2Cl(g)\xrightarrow{{}}C{{l}_{2}}\left( g \right)\] |
| We know that, |
| \[C{{l}_{2}}(g)\xrightarrow{{}}2Cl\left( g \right)\]is endothermic reaction because it requires energy to break bond. |
| So reverse reaction is exothermic \[{{\Delta }_{r}}H<0\] |
| Also, two gaseous atom combine together to form 1 gaseous molecule. |
| So, randomness \[{{\Delta }_{r}}S<0\] |
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