A) \[8\times {{10}^{4}}\,cal/K\]
B) 80 cal/K
C) 293 cal/K
D) 273 cal/K
Correct Answer: C
Solution :
Change in entropy \[\Delta S=\frac{ml}{T}=\frac{1000\times 80}{273}=293\,\,cal\,\,{{K}^{-1}}\]You need to login to perform this action.
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