NEET Physics Two Dimensional Motion NEET PYQ-Two Dimensional Relative Motion

  • question_answer
    A particle has initial velocity \[(2i+3j)\] and acceleration \[(0.3i+0.2j)\]. The magnitude of velocity after 10 s will be        [AIPMT (S) 2012]

    A) \[9\sqrt{2}\] units

    B) \[5\sqrt{2}\] units

    C) 5 units

    D) 9 units

    Correct Answer: B

    Solution :

    From the equation of motion, we knows
    \[\mathbf{v}=\mathbf{u}=\mathbf{a}t\] Given,
    \[\mathbf{v}=(2\mathbf{i}+3\mathbf{j})\]          and            \[\mathbf{a}=(0.3\mathbf{i}+0.2\mathbf{j})\]
                \[\mathbf{v}=(2\mathbf{i}+3\mathbf{j})+(0.3\mathbf{i}+0.2\mathbf{j})\times 10\]
                \[\mathbf{v}=5\mathbf{i}+5\mathbf{j}\] \[(\because v=u+at)\]
                            \[v=5\sqrt{2}\] units


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