A) \[{{30}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{0}^{o}}\]
Correct Answer: C
Solution :
Key Idea: Slope of the path of the particle gives the measure of angle required. |
Draw the situation as shown. OA represents the path of the particle starting from origin \[O(0,\text{ }0)\]. Draw a perpendicular from point A to x-axis. Let path of makes an angle \[\theta \] with the x-axis, then \[\tan \theta =\]slope of line OA |
\[=\frac{AB}{OB}=\frac{3}{\sqrt{3}}=\sqrt{3}\] |
or \[\theta ={{60}^{o}}\] |
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