NEET Physics Two Dimensional Motion NEET PYQ-Two Dimensional Relative Motion

  • question_answer
    A ship A is moving Westwards with a speed of \[10\,km\,{{h}^{-1}}\] and a ship B 100 km South of A, is moving Northwards with a speed of \[10\,km\,{{h}^{-1}}\]. The time after which the distance between them becomes shortest is  [NEET 2015 ]

    A) 0 h       

    B) 5 h

    C) \[5\sqrt{2}h\]

    D) \[10\sqrt{2}h\]

    Correct Answer: B

    Solution :

    It is clear from the diagram that the shortest distance between the ship A and B is PQ.
    Here       \[\sin {{45}^{{}^\circ }}=\frac{PQ}{OQ}\]
    \[\Rightarrow \]   \[PQ=100\times \frac{1}{\sqrt{2}}=50\sqrt{2}m\]
    So, time taken for them to reach shortest path is

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