A) 12.5 cm
B) 8 cm
C) 13.2 cm
D) 16 cm
Correct Answer: C
Solution :
[c] For closed organ pipe, third harmonic |
\[\text{=}\frac{3v}{4l}\] |
For open organ pipe, fundamental frequency |
\[=\frac{v}{2l'}\] |
Given, |
\[\frac{3v}{4l}=\frac{v}{2l'}\] |
\[\Rightarrow l'=\frac{4l}{3\times 2}=\frac{2l}{3}\] |
\[=\frac{2\times 20}{3}=13.33cm\] |
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