A) 12
B) 0
C) 1
D) 6
Correct Answer: D
Solution :
| Let \[{{\lambda }_{1}}=5.0\,m,\,v=330\,m/s\] and \[{{\lambda }_{2}}=5.5\,m\] |
| The relation between frequency, wavelength and velocity is given by |
| \[v\,=n\,\lambda \] |
| \[\Rightarrow \] \[n=\frac{v}{\lambda }\] ...(i) |
| The frequency corresponding to wavelength \[{{\lambda }_{1}},\] |
| \[{{n}_{1}}=\frac{v}{{{\lambda }_{1}}}=\frac{330}{5.0}=66\,Hz\] |
| The frequency corresponding to wavelength \[{{\lambda }_{2}},\] |
| \[{{n}_{2}}=\frac{v}{{{\lambda }_{2}}}=\frac{330}{5.5}=60\,Hz\] |
| Hence, no. of bears per second |
| \[={{n}_{1}}-{{n}_{2}}\] |
| \[=66-60\] |
| \[=6\] |
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