A) 2
B) 4
C) \[\frac{1}{2}\]
D) 1
Correct Answer: A
Solution :
Sabine's formula for reverberation time is |
\[T=\frac{0.16\,V}{\Sigma as}\] |
where V is volume of hall in \[{{m}^{3}}\]. |
\[\Sigma as={{a}_{1}}{{s}_{1}}+{{a}_{2}}{{s}_{2}}+......=\] |
total absorption of the hall (room) |
Here, \[{{s}_{1}},{{s}_{2}},{{s}_{3}}....\] are surface areas of the absorbers and \[{{a}_{1}},{{a}_{2}},{{a}_{3}}\]....... are their respective absorption coefficients |
\[\therefore \] \[\frac{T'}{T}=\frac{V'}{s'}\times \frac{s}{V}\] |
\[=\frac{{{(2)}^{3}}}{{{(2)}^{2}}}=\frac{8}{4}=2\] |
Hence, \[T'=2T=2\times 1=2s\] |
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