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NEET Physics Wave Mechanics NEET PYQ-Wave Mechanics

  • question_answer
    In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:                                                                                               [NEET 2020]

    A)  524 Hz

    B)  536 Hz

    C)  537 Hz            

    D) 523 Hz

    Correct Answer: A

    Solution :

              
    [a] Difference of \[{{f}_{A}}\]and \[{{f}_{B}}\] is 6 Hz
    If tension decreases, \[{{f}_{B}}\] decreases and becomes \[f_{B}^{'}\] .
    Now, difference of \[{{f}_{A}}\] and \[f_{B}^{'}=7\text{ }Hz\] (increases)
    So, \[{{f}_{A}}>{{f}_{B}}\]
    \[{{f}_{A}}{{f}_{B}}=6\text{ }Hz\]
    \[{{f}_{A}}=530\text{ }Hz\]
    \[{{f}_{B}}=524\text{ }Hz\](original)


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