A) 2.1 mm
B) 1.9 mm
C) 1.8 mm
D) 1.7 mm
Correct Answer: B
Solution :
| [b] Angular width \[=\frac{\lambda }{d}\] |
| \[0.20{}^\circ =\frac{\lambda }{2mm}\] (i) |
| \[0.21{}^\circ =\frac{\lambda }{d}\] (ii) |
| Dividing we get, \[\frac{0.20}{0.21}=\frac{d}{2mm}\] |
| \[\therefore d=1.9mm\] |
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