A) 50%
B) 75%
C) 33%
D) 90%
Correct Answer: B
Solution :
Efficiency of the system is |
\[\eta =\frac{\text{output}\,\,\text{work}}{\text{input}\,\,\text{work}}\] |
Input work \[=Fs=250\times 12\] |
Output work \[=mgh=75\times 10\times 3\] |
So, \[\eta =\frac{75\times 10\times 3}{250\times 12}=0.75=75%\] |
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