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NEET NEET SOLVED PAPER 2013

  • question_answer
    A body of mass m taken from the earth's surface to the height equal to twice the radius (R) of the earth. The change is potential energy of body will be 

    A) \[mg2R\]

    B) \[\frac{2}{3}mgR\]

    C) \[3mgR\]

    D) \[\frac{1}{3}mgR\]

    Correct Answer: B

    Solution :

    Change in potential energy \[\Delta U=-\frac{GMm}{R+2R}-\left( -\frac{GMm}{R} \right)\] \[=-\frac{GMm}{3R}+\frac{GMm}{R}\] \[=\frac{2GMm}{3R}=\frac{2}{3}mgR\] \[\left[ \because g=\frac{GM}{{{R}^{2}}} \right]\]


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