A) \[\frac{m{{a}_{0}}}{e}west,\frac{2m{{a}_{0}}}{e{{v}_{0}}}up\]
B) \[\frac{m{{a}_{0}}}{e}west,\frac{2m{{a}_{0}}}{e{{v}_{0}}}dwon\]
C) \[\frac{m{{a}_{0}}}{e}east,\frac{3m{{a}_{0}}}{e{{v}_{0}}}up\]
D) \[\frac{m{{a}_{0}}}{e}east,\frac{3m{{a}_{0}}}{e{{v}_{0}}}down\]
Correct Answer: B
Solution :
Initial acceleration,\[{{a}_{0}}=\frac{eE}{m}\] ?(i) \[\Rightarrow \]\[E=\frac{{{a}_{0}}m}{e}\therefore \frac{e{{v}_{0}}B+eE}{m}=3{{a}_{0}}\] Or \[e{{v}_{0}}B+eE=3{{a}_{0}}m\] \[\therefore \]\[e{{v}_{0}}B=3m{{a}_{0}}-eE\] \[\Rightarrow \] \[=3m{{a}_{0}}-m{{a}_{0}}\][from eq. (1)] \[\Rightarrow \] \[e{{v}_{0}}B=2m{{a}_{0}}\] \[\therefore \] \[B=\frac{2m{{a}_{0}}}{e{{v}_{0}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
